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NEET CHEMISTRYSome Basic Concepts of ChemistryEasy

Question

Which of the following has the greatest number of molecules?

A

64 g SO₂

B

44 g CO₂

C

48 g O₃

D

8 g H₂

Step-by-Step Solution

  1. Identify the Formula: The number of molecules (NN) in a given mass (mm) of a substance is calculated using the number of moles (nn) and Avogadro's constant (NA6.022×1023 mol1N_A \approx 6.022 \times 10^{23} \text{ mol}^{-1}). n=Mass (g)Molar Mass (g/mol)n = \frac{\text{Mass (g)}}{\text{Molar Mass (g/mol)}} N=n×NAN = n \times N_A [Class 12 Chemistry, Ch 1, Example 1.1; Class 11 Physics, Appendix A 3]
  2. Calculate Moles for each option:
  • Option A (64 g SO264\text{ g SO}_2): Molar Mass of SO2=32+2(16)=64 g/mol\text{SO}_2 = 32 + 2(16) = 64\text{ g/mol}. n=6464=1 mol    1NA moleculesn = \frac{64}{64} = 1\text{ mol} \implies 1 N_A \text{ molecules}
  • Option B (44 g CO244\text{ g CO}_2): Molar Mass of CO2=12+2(16)=44 g/mol\text{CO}_2 = 12 + 2(16) = 44\text{ g/mol}. n=4444=1 mol    1NA moleculesn = \frac{44}{44} = 1\text{ mol} \implies 1 N_A \text{ molecules}
  • Option C (48 g O348\text{ g O}_3): Molar Mass of O3=3(16)=48 g/mol\text{O}_3 = 3(16) = 48\text{ g/mol}. n=4848=1 mol    1NA moleculesn = \frac{48}{48} = 1\text{ mol} \implies 1 N_A \text{ molecules}
  • Option D (8 g H28\text{ g H}_2): Molar Mass of H2=2(1)=2 g/mol\text{H}_2 = 2(1) = 2\text{ g/mol}. n=82=4 mol    4NA moleculesn = \frac{8}{2} = 4\text{ mol} \implies 4 N_A \text{ molecules}
  1. Conclusion: 8 g of H28\text{ g of H}_2 contains the greatest number of molecules (4NA4 N_A).

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Some Basic Concepts of Chemistry. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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