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NEET CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques Easy

Question

Which of the following pairs of species have the same bond order?

A

O2−_2^-, NO+^+

B

CN−^-, CO

C

N2_2, O2−_2^-

D

CO, NO

Step-by-Step Solution

  1. Isoelectronic Principle: Species having the same number of total electrons are called isoelectronic. Isoelectronic species usually have the same bond order .
  2. Analyze Option B (CN−CN^- and COCO):
  • CN−CN^-: Number of electrons = 6 (C) + 7 (N) + 1 (negative charge) = 14 electrons.
  • COCO: Number of electrons = 6 (C) + 8 (O) = 14 electrons.
  • Since both have 14 electrons (isoelectronic with N2N_2), they both have a bond order of 3.
  1. Analyze other options:
  • Option A: O2−O_2^- (17 e−e^-) has B.O. = 1.5, while NO+NO^+ (14 e−e^-) has B.O. = 3.
  • Option C: N2N_2 (14 e−e^-) has B.O. = 3, while O2−O_2^- (17 e−e^-) has B.O. = 1.5.
  • Option D: COCO (14 e−e^-) has B.O. = 3, while NONO (15 e−e^-) has B.O. = 2.5.
  1. Conclusion: The pair CN−CN^- and COCO have the same bond order.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Organic Chemistry – Some Basic Principles and Techniques . Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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