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NEET CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques Easy

Question

Which of the following species has a bond angle of 120^\circ?

A

SF6_6

B

NCl3_3

C

BCl3_3

D

PH3_3

Step-by-Step Solution

  1. Analyze BCl3_3: The central Boron atom has 3 valence electrons. It forms 3 sigma bonds with Chlorine atoms and has zero lone pairs. According to VSEPR theory, a molecule with 3 bond pairs and 0 lone pairs (AB3_3 type) adopts a trigonal planar geometry. The hybridisation is sp2^2 and the bond angle is exactly 120^\circ .
  2. Analyze other options:
  • SF6_6: Sulphur is sp3^3d2^2 hybridised with octahedral geometry. Bond angles are 90^\circ .
  • NCl3_3: Nitrogen is sp3^3 hybridised with 1 lone pair (Pyramidal geometry). Bond angle is less than 109.5^\circ .
  • PH3_3: Phosphorus is sp3^3 hybridised (or unhybridised per Drago's rule) with 1 lone pair. Bond angle is close to 93^\circ (Pyramidal) .
  1. Conclusion: Only BCl3_3 has a bond angle of 120^\circ.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Organic Chemistry – Some Basic Principles and Techniques . Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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