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NEET CHEMISTRYOrganic Chemistry – Some Basic Principles and Techniques Medium

Question

Which one of the following pairs of species have the same bond order?

A

CO\text{CO}, NO\text{NO}

B

O2\text{O}_2^-, CN\text{CN}^-

C

CN\text{CN}^-, NO+\text{NO}^+

D

N+\text{N}^+, CN+\text{CN}^+

Step-by-Step Solution

Species with the same number of electrons (isoelectronic species) generally have the same bond order according to Molecular Orbital Theory.

  • CN\text{CN}^-: The total number of electrons is 6 (C)+7 (N)+1 (negative charge)=146 \text{ (C)} + 7 \text{ (N)} + 1 \text{ (negative charge)} = 14 electrons. Its bond order is 3.
  • NO+\text{NO}^+: The total number of electrons is 7 (N)+8 (O)1 (positive charge)=147 \text{ (N)} + 8 \text{ (O)} - 1 \text{ (positive charge)} = 14 electrons. Its bond order is also 3.

Let's check the other pairs:

  • CO\text{CO} has 14 electrons (bond order 3) while NO\text{NO} has 15 electrons (bond order 2.5).
  • O2\text{O}_2^- has 17 electrons (bond order 1.5) while CN\text{CN}^- has 14 electrons (bond order 3). Therefore, CN\text{CN}^- and NO+\text{NO}^+ are the pair with the same bond order.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Organic Chemistry – Some Basic Principles and Techniques . Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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