A body is thrown vertically up from the ground. It reaches a maximum height of $100 ext{ m}$ in $5 ext{ s}

Question

A body is thrown vertically up from the ground. It reaches a maximum height of $100 	ext{ m}$ in $5 	ext{ s}$. After what time will it reach the ground from the position of maximum height?

Accepted Answer

1. **Symmetry of Vertical Motion:** For an object thrown vertically upwards under the influence of constant gravity (neglecting air resistance), the time taken to reach the maximum height (time of ascent) is equal to the time taken to fall from the maximum height back to the point of projection (time of descent).
2. **Given Data:**
   - Time of ascent ($t_{up}$) = $5 	ext{ s}$.
3. **Calculation:**
   - Time of descent ($t_{down}$) = $t_{up}$.
   - Therefore, the time taken to reach the ground from the maximum height is $5 	ext{ s}$ .

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