A body of mass $60 ext{ g}$ experiences a gravitational force of $3.0 ext{ N}$ when placed at a particular

Question

A body of mass $60 	ext{ g}$ experiences a gravitational force of $3.0 	ext{ N}$ when placed at a particular point. The magnitude of the gravitational field intensity at that point is:

Accepted Answer

1. **Definition:** Gravitational field intensity ($E$ or $g$) at a point is defined as the gravitational force experienced by a unit mass placed at that point. The formula is given by $E = \frac{F}{m}$.
2. **Given Data:**
   - Gravitational Force, $F = 3.0 	ext{ N}$.
   - Mass of the body, $m = 60 	ext{ g}$.
3. **Unit Conversion:** Convert mass into SI units (kg).
   $$ m = 60 	imes 10^{-3} 	ext{ kg} = 0.06 	ext{ kg} $$
4. **Calculation:**
   Substitute the values into the formula:
   $$ E = \frac{3.0 	ext{ N}}{0.06 	ext{ kg}} = \frac{300}{6} 	ext{ N/kg} = 50 	ext{ N/kg} $$

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