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NEET PHYSICSGRAVITATIONEasy

Question

A body weighs 200 N200 \text{ N} on the surface of the earth. How much will it weigh halfway down the centre of the earth?

A

100 N100 \text{ N}

B

150 N150 \text{ N}

C

200 N200 \text{ N}

D

250 N250 \text{ N}

Step-by-Step Solution

  1. Formula for Gravity at Depth: The acceleration due to gravity (gdg_d) at a depth dd below the surface of the Earth is given by the formula: gd=g(1dRE)g_d = g \left( 1 - \frac{d}{R_E} \right) where gg is the acceleration due to gravity on the surface and RER_E is the radius of the Earth [Eq. 7.19].
  2. Given Data:
  • Weight on surface, W=mg=200 NW = mg = 200 \text{ N}.
  • Depth, d=RE2d = \frac{R_E}{2} (halfway to the centre).
  1. Calculation: The new weight WdW_d is mgdm g_d. Wd=mg(1RE/2RE)W_d = m g \left( 1 - \frac{R_E/2}{R_E} \right) Wd=W(112)W_d = W \left( 1 - \frac{1}{2} \right) Wd=200(0.5)=100 NW_d = 200 \left( 0.5 \right) = 100 \text{ N}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from GRAVITATION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSGRAVITATIONweighssurfacehalfwaycentre

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