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NEET PHYSICSMOTION IN A STRAIGHT LINEMedium

Question

A man throws balls with the same speed vertically upwards one after the other at an interval of 2 seconds. What should be the speed of the throw so that more than two balls are in the sky at any time? (Given g=9.8 m/s2g=9.8 \text{ m/s}^2)

A

At least 0.8 m/s

B

Any speed less than 19.6 m/s

C

Only with speed 19.6 m/s

D

More than 19.6 m/s

Step-by-Step Solution

  1. Analyze the Condition: For more than two balls (i.e., at least 3 balls) to be in the sky simultaneously, the first ball must remain in the air when the third ball is thrown.
  2. Time Intervals: Ball 1 is thrown at t=0t=0. Ball 2 is thrown at t=2 st=2\text{ s}.
  • Ball 3 is thrown at t=4 st=4\text{ s}.
  1. Apply Kinematics: The time of flight (TT) of the first ball must be greater than 4 seconds so that it is still in the air when the third ball is projected at t=4 st=4\text{ s}.
  • Formula for time of flight: T=2ugT = \frac{2u}{g} .
  1. Solve for Speed (uu): T>4T > 4 2ug>4\frac{2u}{g} > 4 u>2gu > 2g u>2×9.8u > 2 \times 9.8 u>19.6 m/su > 19.6 \text{ m/s}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEthrowsverticallyupwardsintervalseconds

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