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NEET PHYSICSMOTION IN A STRAIGHT LINEEasy

Question

A packet is dropped from a balloon which is going upwards with the velocity 12 m/s12 \text{ m/s}, the velocity of the packet after 2 seconds2 \text{ seconds} will be:

A

–12 m/s

B

12 m/s

C

–7.6 m/s

D

7.6 m/s

Step-by-Step Solution

  1. Identify Initial Conditions: When an object is dropped from a moving body (like a balloon), it inherits the velocity of that body at the instant of release.
  • Initial velocity of the packet, u=+12 m/su = +12 \text{ m/s} (taking upward direction as positive).
  1. Identify Acceleration: The packet is under the influence of gravity.
  • Acceleration, a=g=9.8 m/s2a = -g = -9.8 \text{ m/s}^2 (acting downwards).
  1. Apply Kinematic Equation: To find the final velocity (vv) after time t=2 st = 2 \text{ s}, use the first equation of motion: v=u+atv = u + at v=12+(9.8)(2)v = 12 + (-9.8)(2) v=1219.6v = 12 - 19.6 v=7.6 m/sv = -7.6 \text{ m/s} The negative sign indicates that the packet is moving downwards with a speed of 7.6 m/s7.6 \text{ m/s} .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEpacketdroppedballoonupwardsvelocity

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