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NEET PHYSICSMOTION IN A STRAIGHT LINEEasy

Question

A scooter accelerates from rest for time t1t_1 at constant rate a1a_1 and then retards at constant rate a2a_2 for time t2t_2 and comes to rest. The correct value of t1t2\frac{t_1}{t_2} will be:

A

\frac{a_1 + a_2}{a_2}

B

\frac{a_2}{a_1}

C

\frac{a_1}{a_2}

D

\frac{a_1 + a_2}{a_1}

Step-by-Step Solution

  1. Analyze Phase 1 (Acceleration): The scooter starts from rest (u=0u=0) and accelerates at a1a_1 for time t1t_1. Using the first equation of motion : v=u+atvmax=0+a1t1v = u + at \Rightarrow v_{max} = 0 + a_1 t_1 vmax=a1t1v_{max} = a_1 t_1
  2. Analyze Phase 2 (Retardation): The scooter starts with velocity vmaxv_{max} and decelerates at a2a_2 (acceleration =a2= -a_2) for time t2t_2 until it stops (vfinal=0v_{final} = 0). v=u+at0=vmaxa2t2v = u + at \Rightarrow 0 = v_{max} - a_2 t_2 vmax=a2t2v_{max} = a_2 t_2
  3. Equate and Solve: Since the maximum velocity reached is the same for both phases: a1t1=a2t2a_1 t_1 = a_2 t_2 t1t2=a2a1\frac{t_1}{t_2} = \frac{a_2}{a_1}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEscooteracceleratesconstantretardsconstant

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