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NEET PHYSICSNUCLEIEasy

Question

At some instant, the number of radioactive atoms in a sample is N0N_0 and after time tt, the number decreases to NN. It is found that the graphical representation lnN\ln N versus tt along the yy and xx axis respectively is a straight line. Then the slope of this line is:

A

λ\lambda

B

λ-\lambda

C

λ1\lambda^{-1}

D

λ1-\lambda^{-1}

Step-by-Step Solution

  1. Identify the Decay Law: Radioactive decay follows first-order kinetics. The number of undecayed nuclei NN at time tt is given by the equation N=N0eλtN = N_0 e^{-\lambda t}, where λ\lambda is the decay constant .
  2. Linearize the Equation: To interpret the graph, take the natural logarithm (ln\ln) of both sides: lnN=ln(N0eλt)\ln N = \ln(N_0 e^{-\lambda t}) lnN=lnN0+ln(eλt)\ln N = \ln N_0 + \ln(e^{-\lambda t}) lnN=λt+lnN0\ln N = -\lambda t + \ln N_0
  3. Compare with Straight Line Equation: This equation is in the form y=mx+cy = mx + c, which represents a straight line. Matching the terms:
  • y=lnNy = \ln N
  • x=tx = t
  • mm (slope) = λ-\lambda
  • cc (intercept) = lnN0\ln N_0
  1. Conclusion: The slope of the graph of lnN\ln N versus tt is λ-\lambda .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from NUCLEI. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSNUCLEIinstantnumberradioactivesamplenumber

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