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NEET PHYSICSGRAVITATIONMedium

Question

At what height from the surface of earth the gravitation potential and the value of g are -5.4 × 10^7 J kg^-1 and 6.0 m s^-2 respectively? (Take the radius of earth as 6400 km.)

A

1600 km

B

1400 km

C

2000 km

D

2600 km

Step-by-Step Solution

Let rr be the distance from the center of the Earth to the point at height hh. The gravitational potential VV at distance rr is given by magnitude V=GMr|V| = \frac{GM}{r}. The acceleration due to gravity ghg_h at distance rr is given by gh=GMr2g_h = \frac{GM}{r^2}. Dividing the magnitude of potential by the acceleration gives the distance rr: Vgh=GM/rGM/r2=r\frac{|V|}{g_h} = \frac{GM/r}{GM/r^2} = r. Substituting the given values: r=5.4×107 J/kg6.0 m/s2=0.9×107 m=9×106 m=9000 kmr = \frac{5.4 \times 10^7 \text{ J/kg}}{6.0 \text{ m/s}^2} = 0.9 \times 10^7 \text{ m} = 9 \times 10^6 \text{ m} = 9000 \text{ km}. The height hh from the surface is h=rRh = r - R, where RR is the Earth's radius (6400 km). h=9000 km6400 km=2600 kmh = 9000 \text{ km} - 6400 \text{ km} = 2600 \text{ km}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from GRAVITATION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSGRAVITATIONheightsurfacegravitationpotentialrespectively

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