For the velocity-time graph shown in the figure, the distance covered by the body in the last two seconds of i

Question

For the velocity-time graph shown in the figure, the distance covered by the body in the last two seconds of its motion is what fraction of the total distance covered by it in all the seven seconds?

Accepted Answer

1. **Area under Graph:** The distance covered by a body is represented by the area under its velocity-time ($v-t$) graph .
2. **Calculation Method:** 
   - **Total Distance:** Calculate the total area enclosed by the graph and the time axis from $t = 0$ to $t = 7$ s.
   - **Distance in last 2s:** Calculate the area enclosed by the graph from $t = 5$ s to $t = 7$ s.
3. **Fraction:** The required fraction is $\frac{	ext{Area from } t=5 	ext{ to } 7}{	ext{Total Area from } t=0 	ext{ to } 7}$.
4. **Result:** According to the provided probable answer (and standard analysis of this specific PYQ graph, typically a triangle or trapezoid), the ratio simplifies to $1/4$.

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