If a body is thrown up with the velocity of $15 ext{ m/s}$, then the maximum height attained by the body is:

Question

If a body is thrown up with the velocity of $15 	ext{ m/s}$, then the maximum height attained by the body is: (assume $g = 10 	ext{ m/s}^2$)

Accepted Answer

1. **Identify Given Values:**
   - Initial velocity, $u = 15 	ext{ m/s}$.
   - Acceleration due to gravity, $g = 10 	ext{ m/s}^2$ (acting downwards, so $a = -g$).
   - Final velocity at maximum height, $v = 0$.
2. **Select Kinematic Equation:** Use the equation that relates velocity, acceleration, and displacement: 
   $$ v^2 = u^2 + 2as $$
   Here, displacement $s = H$ (maximum height) .
3. **Substitute and Solve:**
   $$ 0^2 = (15)^2 + 2(-10)H $$
   $$ 0 = 225 - 20H $$
   $$ 20H = 225 $$
   $$ H = \frac{225}{20} = 11.25 	ext{ m} $$ .

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