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NEET PHYSICSMOVING CHARGES AND MAGNETISMEasy

Question

If a charged particle (charge q) is moving in a circle of radius R at a uniform speed v, then the value of its associated magnetic moment \mu will be:

A

\frac{qvR}{2}

B

qvR^2

C

\frac{qvR^2}{2}

D

qvR

Step-by-Step Solution

  1. Current Equivalent: A charged particle qq moving in a circle constitutes a current II. The current is the rate of flow of charge: I=q/TI = q/T, where TT is the time period of revolution .
  2. Time Period: For a particle moving with speed vv in a circle of radius RR, the time period is T=2πRvT = \frac{2\pi R}{v}. Substituting this into the current equation: I=q2πR/v=qv2πRI = \frac{q}{2\pi R / v} = \frac{qv}{2\pi R}
  3. Magnetic Moment Formula: The magnetic dipole moment μ\mu associated with a current loop is given by μ=I×A\mu = I \times A, where AA is the area of the loop . A=πR2A = \pi R^2
  4. Calculation: Substituting the expressions for II and AA: μ=(qv2πR)(πR2)\mu = \left( \frac{qv}{2\pi R} \right) (\pi R^2) μ=qvR2\mu = \frac{qvR}{2}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOVING CHARGES AND MAGNETISM. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOVING CHARGES AND MAGNETISMchargedparticlechargemovingcircle

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