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NEET PHYSICSMOVING CHARGES AND MAGNETISMEasy

Question

Ionized hydrogen atoms and α\alpha-particles with the same momenta enter perpendicular to a constant magnetic field, BB. The ratio of their path radii rH:rαr_H : r_\alpha will be:

A

1 : 4

B

2 : 1

C

1 : 2

D

4 : 1

Step-by-Step Solution

  1. Radius Formula: The radius (rr) of the circular path of a charged particle moving perpendicular to a uniform magnetic field (BB) is given by the equation: r=mvqB=pqBr = \frac{mv}{qB} = \frac{p}{qB} where mm is mass, vv is velocity, qq is charge, and p=mvp = mv is momentum .
  2. Proportionality: Since the momentum (pp) and the magnetic field (BB) are the same for both particles, the radius is inversely proportional to the charge (qq). r1qr \propto \frac{1}{q}
  3. Particle Charges:
  • Ionized Hydrogen atom (H+H^+) has a charge qH=+eq_H = +e.
  • α\alpha-particle (He2+He^{2+}) has a charge qα=+2eq_\alpha = +2e.
  1. Calculation: rHrα=qαqH=2ee=21\frac{r_H}{r_\alpha} = \frac{q_\alpha}{q_H} = \frac{2e}{e} = \frac{2}{1} Thus, the ratio is 2:1.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOVING CHARGES AND MAGNETISM. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOVING CHARGES AND MAGNETISMionizedhydrogenalphaparticlesmomentaperpendicular

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