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NEET PHYSICSATOMSMedium

Question

Match List-I with List-II.

List-I (Spectral Lines of Hydrogen for transitions from) A. n₂=3 to n₁=2 B. n₂=4 to n₁=2 C. n₂=5 to n₁=2 D. n₂=6 to n₁=2

List-II (Wavelength (nm)) I. 410.2 II. 434.1 III. 656.3 IV. 486.1

Choose the correct answer from the options given below:

A

A-III, B-IV, C-II, D-I

B

A-IV, B-III, C-I, D-II

C

A-I, B-II, C-III, D-IV

D

A-II, B-I, C-IV, D-III

Step-by-Step Solution

These transitions correspond to the Balmer series (transitions to n1=2n_1=2) in the hydrogen spectrum . The wavelength (λ\lambda) is inversely proportional to the energy difference (ΔE\Delta E) of the transition (ΔE=hc/λ\Delta E = hc/\lambda).

  1. Transition A (n2=3→n1=2n_2=3 \to n_1=2): This represents the smallest energy gap in the series, corresponding to the longest wavelength (Red line, HαH_\alpha). Matches III (656.3 nm).
  2. Transition D (n2=6→n1=2n_2=6 \to n_1=2): This represents the largest energy gap among the given options, corresponding to the shortest wavelength (Violet line, HδH_\delta). Matches I (410.2 nm).
  3. Transition B (n2=4→n1=2n_2=4 \to n_1=2): Intermediate energy (HβH_\beta). Matches IV (486.1 nm).
  4. Transition C (n2=5→n1=2n_2=5 \to n_1=2): Intermediate energy (HγH_\gamma). Matches II (434.1 nm).

Therefore, the correct matching is A-III, B-IV, C-II, D-I.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from ATOMS. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSATOMSlistiispectralhydrogentransitionslistii

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