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NEET PHYSICSGRAVITATIONEasy

Question

Starting from the centre of the earth, having radius R, the variation of g (acceleration due to gravity) is shown by:

A

Graph showing constant g

B

Graph showing linear increase (g \propto r) for r < R and curvilinear decrease (g \propto 1/r²) for r > R

C

Graph showing linear decrease

D

Graph showing parabolic increase

Step-by-Step Solution

The variation of acceleration due to gravity (gg) with distance rr from the centre of the Earth is derived as follows:

  1. Inside the Earth (r<Rr < R): Assuming uniform density, gg is directly proportional to the distance from the centre. The formula is g=GMR3rg = \frac{GM}{R^3}r, which implies grg \propto r. This represents a straight line passing through the origin.
  2. At the Surface (r=Rr = R): The value of gg reaches its maximum, gsurface=GMR2g_{surface} = \frac{GM}{R^2}.
  3. Outside the Earth (r>Rr > R): The value of gg decreases with distance according to the inverse square law. The formula is g=GMr2g = \frac{GM}{r^2}, which implies g1r2g \propto \frac{1}{r^2}. This represents a hyperbolic curve decreasing asymptotically towards zero.

Therefore, the correct graph shows a linear increase up to r=Rr=R followed by a curvilinear decrease.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from GRAVITATION. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSGRAVITATIONstartingcentrehavingradiusvariation

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