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NEET PHYSICSMOTION IN A STRAIGHT LINEEasy

Question

The displacement of a particle as a function of time is shown in the figure. The figure shows that

A

The particle starts with certain velocity but the motion is retarded and finally the particle stops

B

The velocity of the particle is constant throughout

C

The acceleration of the particle is constant throughout

D

The particle starts with constant velocity, then motion is accelerated and finally the particle moves with another constant velocity

Step-by-Step Solution

  1. Slope represents Velocity: In a displacement-time (x−tx-t) graph, the instantaneous velocity of the particle is defined as the slope of the tangent to the curve at any specific instant (v=dxdtv = \frac{dx}{dt}) .
  2. Graph Analysis:
  • Initial State: The description implies the graph starts with a specific positive slope at t=0t=0, indicating the particle has an initial non-zero velocity.
  • Retardation: As time increases, if the slope of the curve decreases (the curve becomes less steep), it indicates that the velocity is decreasing. A decreasing velocity signifies retardation (negative acceleration).
  • Stopping: Finally, if the tangent to the curve becomes horizontal (slope =0= 0), the velocity becomes zero, meaning the particle stops.
  1. Conclusion: The option describing a particle starting with a velocity, undergoing retardation, and stopping corresponds to a graph with an initially positive slope that gradually decreases to zero.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEdisplacementparticlefunctionfigurefigure

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