The distance travelled by a particle starting from rest and moving with an acceleration 4/3 ms⁻², in the third

Question

The distance travelled by a particle starting from rest and moving with an acceleration 4/3 ms⁻², in the third second is

Accepted Answer

1.  **Identify Given Values:**
    *   Initial velocity ($u$) = 0 (starts from rest).
    *   Acceleration ($a$) = $4/3 	ext{ ms}^{-2}$.
    *   Time interval ($n$) = 3rd second.
2.  **Select Formula:**
    The distance travelled in the $n$-th second ($S_n$) for uniformly accelerated motion is given by:
    $$ S_n = u + \frac{a}{2}(2n - 1) $$ 
3.  **Calculation:**
    Substitute the values into the formula:
    $$ S_{3rd} = 0 + \frac{4/3}{2} (2 	imes 3 - 1) $$
    $$ S_{3rd} = \frac{2}{3} (6 - 1) $$
    $$ S_{3rd} = \frac{2}{3} 	imes 5 = \frac{10}{3} 	ext{ m} $$

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