back to directory
NEET PHYSICSOscillationsMedium

Question

Two points are located at a distance of 10 m10\text{ m} and 15 m15\text{ m} from the source of oscillation. The period of oscillation is 0.05 s0.05\text{ s} and the velocity of the wave is 300 m/s300\text{ m/s}. What is the phase difference between the oscillations of two points?

A

π3\frac{\pi}{3}

B

2π3\frac{2\pi}{3}

C

π\pi

D

π6\frac{\pi}{6}

Step-by-Step Solution

  1. Identify Given Values: The distances of the two points from the source are x1=10 mx_1 = 10\text{ m} and x2=15 mx_2 = 15\text{ m}. The path difference is Δx=1510=5 m\Delta x = 15 - 10 = 5\text{ m}. The time period is T=0.05 sT = 0.05\text{ s} and wave velocity is v=300 m/sv = 300\text{ m/s}.
  2. Calculate Wavelength (λ\lambda): The wavelength is the distance covered by the wave in one time period. λ=v×T=300×0.05=15 m\lambda = v \times T = 300 \times 0.05 = 15\text{ m}.
  3. Calculate Phase Difference (Δϕ\Delta \phi): The relation between phase difference and path difference is given by Δϕ=2πλΔx\Delta \phi = \frac{2\pi}{\lambda} \Delta x . Substituting the values: Δϕ=2π15×5=2π3 radians\Delta \phi = \frac{2\pi}{15} \times 5 = \frac{2\pi}{3} \text{ radians}

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from Oscillations. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSOscillationspointslocateddistancesourceoscillation

More Oscillations Questions

View all

A simple pendulum performs simple harmonic motion about $x = 0$ with an amplitude $a$ and time period $T$. The speed of the pendulum at $x = rac{a}{2}$ will be:

A.$\frac{\pi a \sqrt{3}}{2T}$
B.$\frac{\pi a}{T}$
C.$\frac{3\pi^2 a}{T}$
D.$\frac{\pi a \sqrt{3}}{T}$
MediumSolve

The restoring force of a spring, with a block attached to the free end of the spring, is represented by:

A.
B.
C.4
D.$F = -kx$
EasySolve

The displacement-time ($x-t$) graph of a particle performing simple harmonic motion is shown in the figure. The acceleration of the particle at $t = 2$ s is:

A.$-\frac{\pi^2}{16} \text{ ms}^{-2}$
B.$\frac{\pi^2}{8} \text{ ms}^{-2}$
C.$-\frac{\pi^2}{8} \text{ ms}^{-2}$
D.$\frac{\pi^2}{16} \text{ ms}^{-2}$
EasySolve

A particle executing simple harmonic motion has a kinetic energy of $K = K_0 \cos^2(\omega t)$. The values of the maximum potential energy and the total energy are, respectively:

A.$0$ and $2K_0$
B.$K_0/2$ and $K_0$
C.$K_0$ and $2K_0$
D.$K_0$ and $K_0$
MediumSolve

When two displacements represented by $y_1 = a \sin(\omega t)$ and $y_2 = b \cos(\omega t)$ are superimposed, the motion is:

A.not a simple harmonic
B.simple harmonic with amplitude a/b
C.simple harmonic with amplitude $\sqrt{a^2+b^2}$
D.simple harmonic with amplitude (a+b)/2
MediumSolve

From the given functions, identify the function which represents a periodic motion:

A.$e^{\omega t}$
B.$\log_e(\omega t)$
C.$\sin \omega t + \cos \omega t$
D.$e^{-\omega t}$
EasySolve

A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then, its time period in seconds is:

A.\frac{\sqrt{5}}{\pi}
B.\frac{\sqrt{5}}{2\pi}
C.\frac{4\pi}{\sqrt{5}}
D.\frac{2\pi}{\sqrt{3}}
MediumSolve

Match List-I with List-II. **List-I (Graphs)** (a) Displacement-time graph with decreasing amplitude (Damped) (b) Displacement-time graph with constant amplitude (Undamped) (c) Force-displacement graph (Linear relationship, F = -kx) (d) Energy-time graph (Constant total energy) **List-II (Situations)** (i) Total mechanical energy is conserved (ii) Bob of a pendulum is oscillating under negligible air friction (iii) Restoring force of a spring (iv) Bob of a pendulum is oscillating along with air friction Choose the correct answer from the options given below:

A.(a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
B.(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
C.(a)-(i), (b)-(iv), (c)-(iii), (d)-(ii)
D.(a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
MediumSolve

This neet physics practice question is part of the TopperSquare free question bank. TopperSquare offers 15,000+ chapter-wise NEET MCQs across Physics, Chemistry, and Biology with detailed step-by-step explanations, full mock tests, NEET PYQs (2010–2024), and an AI-powered performance analytics dashboard. browse all neet practice questions → · practice physics sets →

Two points are located at a distance of $10\text{ ... | NEET MCQ | TopperSquare