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NEET PHYSICSMOTION IN A STRAIGHT LINEEasy

Question

Two trains, each 50 m50 \text{ m} long, are travelling in the opposite direction with velocities 10 m/s10 \text{ m/s} and 15 m/s15 \text{ m/s}. The time of crossing is:

A

10 sec

B

4 sec

C

2√3 sec

D

4√3 sec

Step-by-Step Solution

  1. Concept - Relative Velocity: When two objects move in opposite directions, their relative velocity is the sum of their individual speeds.
  • vrelative=v1+v2=10+15=25 m/sv_{relative} = v_1 + v_2 = 10 + 15 = 25 \text{ m/s} .
  1. Total Distance: To cross each other completely, the total distance covered is the sum of the lengths of both trains.
  • d=L1+L2=50+50=100 md = L_1 + L_2 = 50 + 50 = 100 \text{ m}.
  1. Calculate Time: Time taken to cross is given by distance divided by relative speed.
  • t=dvrelative=10025=4 sect = \frac{d}{v_{relative}} = \frac{100}{25} = 4 \text{ sec}.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEtrainstravellingoppositedirectionvelocities

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