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NEET PHYSICSMOTION IN A STRAIGHT LINEEasy

Question

Velocity of a body on reaching the point from which it was projected upwards, is:

A

v=0v=0

B

v=2uv=2u

C

v=0.5uv=0.5u

D

v=−uv=-u

Step-by-Step Solution

  1. Initial Conditions: A body is projected vertically upwards with an initial velocity uu. Let the upward direction be positive (++) and the downward direction be negative (−-). Thus, initial velocity is +u+u.
  2. Displacement Condition: When the body reaches the point of projection, the net displacement (ss) is zero because the final position coincides with the initial position.
  3. Apply Kinematic Equation: Use the third equation of motion v2=u2+2asv^2 = u^2 + 2as .
  • Substituting s=0s = 0, we get: v2=u2+2a(0)v^2 = u^2 + 2a(0) v2=u2v^2 = u^2 v=±uv = \pm u
  1. Determine Sign: Since the body is moving downwards while returning to the projection point, its velocity must be negative (opposite to the direction of projection). Therefore, the final velocity is v=−uv = -u. The magnitude (speed) remains the same, but the direction is reversed .

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from MOTION IN A STRAIGHT LINE. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSMOTION IN A STRAIGHT LINEvelocityreachingprojectedupwards

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