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NEET CHEMISTRYClassification of Elements and Periodicity in PropertiesMedium

Question

The incorrect match among the following is:

A

B < C < N < O (increasing first ionisation enthalpy)

B

I < Br < F < Cl (increasing electron gain enthalpy)

C

Li < Na < K < Rb (increasing metallic radius)

D

Al³⁺ < Mg²⁺ < Na⁺ < F⁻ (increasing ionic size)

Step-by-Step Solution

We evaluate the correctness of each periodic trend:

  1. Ionisation Enthalpy (Period 2): generally increases across a period. However, Nitrogen (2s22p32s^2 2p^3) has a stable half-filled p-orbital configuration, making it harder to remove an electron compared to Oxygen (2s22p42s^2 2p^4). Thus, IE1(N)>IE1(O)IE_1(N) > IE_1(O). The correct order is B<C<O<NB < C < O < N. The given option (B<C<N<OB < C < N < O) is incorrect.
  2. Electron Gain Enthalpy (Group 17): Generally becomes less negative down the group. However, Fluorine is anomalous; due to its small size, strong electron-electron repulsion makes adding an electron less favorable than in Chlorine. Thus, Chlorine has the highest negative electron gain enthalpy. The correct magnitude order is I<Br<F<ClI < Br < F < Cl. This match is correct.
  3. Metallic Radius (Group 1): Radius increases down the group as new shells are added. Order: Li<Na<K<RbLi < Na < K < Rb. This match is correct.
  4. Ionic Size (Isoelectronic Species): For species with the same number of electrons (10e10e^-), radius decreases as nuclear charge (Z) increases. Order: Al3+(Z=13)<Mg2+(Z=12)<Na+(Z=11)<F(Z=9)Al^{3+} (Z=13) < Mg^{2+} (Z=12) < Na^+ (Z=11) < F^- (Z=9). This match is correct.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Classification of Elements and Periodicity in Properties. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYClassification of Elements and Periodicity in Propertiesincorrectfollowing

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The correct sequence of increasing radii is:

A.Ar < K⁺ < Ca²⁺
B.Ca²⁺ < Ar < K⁺
C.Ca²⁺ < K⁺ < Ar
D.K⁺ < Ar < Ca²⁺
EasySolve

Which one of the following represents all isoelectronic species?

A.Na⁺, Cl⁻, O⁻, NO⁺
B.N₂O, N₂O₄, NO⁺, NO
C.Na⁺, Mg²⁺, O⁻, F⁻
D.Ca²⁺, Ar, K⁺, Cl⁻
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The value of electron gain enthalpy of $Na^+$, if $IE_1$ of Na = 5.1 eV, is:

A.+10.2 eV
B.–5.1 eV
C.–10.2 eV
D.+2.55 eV
EasySolve

Be²⁺ is isoelectronic with which of the following ions?

A.H⁺
B.Li⁺
C.Na⁺
D.Mg²⁺
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Identify the correct order of the size of the following species: $Ca^{2+}, K^+, Ar, S^{2-}, Cl^-$

A.$Ca^{2+} < K^+ < Ar < S^{2-} < Cl^-$
B.$Ca^{2+} < K^+ < Ar < Cl^- < S^{2-}$
C.$Ar < Ca^{2+} < K^+ < Cl^- < S^{2-}$
D.$Ca^{2+} < Ar < K^+ < Cl^- < S^{2-}$
MediumSolve

The formation of the oxide ion O²⁻(g) from oxygen atom requires first an exothermic and then an endothermic step as shown below: O(g) + e⁻ → O⁻(g); ΔH° = -141 kJ mol⁻¹ O⁻(g) + e⁻ → O²⁻(g); ΔH° = +780 kJ mol⁻¹ Thus, the process of formation of O²⁻ in gas phase is unfavourable even though O²⁻ is isoelectronic with neon. It is due to the fact that:

A.Electron repulsion outweighs the stability gained by achieving noble gas configuration
B.O⁻ ion has comparatively smaller size than oxygen atom
C.Oxygen is more electronegative
D.Addition of electron in oxygen result in large size of the ion
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Which of the following arrangements is correct for increasing order of electronegativity?

A.Si < C < O < N < F
B.O < F < N < C < Si
C.F < O < N < C < Si
D.Si < C < N < O < F
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The correct order of decreasing second ionization enthalpy of Ti(22), V(23), Cr(24) and Mn(25) is:

A.Cr > Mn > V > Ti
B.V > Mn > Cr > Ti
C.Mn > Cr > Ti > V
D.Ti > V > Cr > Mn
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