A ball is thrown vertically downward with a velocity of $20 ext{ m/s}$ from the top of a tower. It hits the

Question

A ball is thrown vertically downward with a velocity of $20 	ext{ m/s}$ from the top of a tower. It hits the ground after some time with a velocity of $80 	ext{ m/s}$. The height of the tower is : ($g = 10 	ext{ m/s}^2$)

Accepted Answer

$v^2 = u^2 + 2gh$. $v = 80 	ext{ m/s}$, $u = 20 	ext{ m/s}$. $h = \frac{v^2 - u^2}{2g} = \frac{6400 - 400}{20} = 300 	ext{ m}$.

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