Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1 m wi

Question

Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1 m with negligible mass. The centre of mass of the system from the 5 kg particle is nearly at a distance of :

Accepted Answer

Using the center of mass formula $x_{cm} = \frac{m_1x_1 + m_2x_2}{m_1 + m_2}$. With $m_1=5, x_1=0$ and $m_2=10, x_2=100 	ext{ cm}$, we get $x_{cm} = \frac{5(0) + 10(100)}{5+10} = \frac{1000}{15} = 66.66 	ext{ cm} \approx 67 	ext{ cm}$.

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