A short electric dipole has a dipole moment of $16 imes 10^{-9} C m$. The electric potential due to the dipo

Question

A short electric dipole has a dipole moment of $16 	imes 10^{-9} C m$. The electric potential due to the dipole at a point at a distance of $0.6 m$ from the centre of the dipole, situated on a line making an angle of $60^{\circ}$ with the dipole axis is : ($\frac{1}{4\pi \epsilon_0} = 9 	imes 10^9 N m^2/C^2$)

Accepted Answer

$V = \frac{kp \cos 	heta}{r^2}$. $V = \frac{9 	imes 10^9 	imes 16 	imes 10^{-9} 	imes \cos 60^{\circ}}{0.36} = 200 V$

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