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NEET PhysicsGeneralEasy

Question

Light with an average flux of 20 W/cm220 \text{ W/cm}^2 falls on a non-reflecting surface at normal incidence having surface area 20 cm220 \text{ cm}^2. The energy received by the surface during time span of 1 minute is :

1

10×103 J10 \times 10^3 \text{ J}

2

12×103 J12 \times 10^3 \text{ J}

3

24×103 J24 \times 10^3 \text{ J}

4

48×103 J48 \times 10^3 \text{ J}

Step-by-Step Solution

Energy received = Intensity ×\times Area ×\times Time. Given Intensity = 20 W/cm220 \text{ W/cm}^2, Area = 20 cm220 \text{ cm}^2, Time = 1 minute = 60 seconds. Energy = 20×20×60=24000 J=24×103 J20 \times 20 \times 60 = 24000 \text{ J} = 24 \times 10^3 \text{ J}.

Exam Context & Concepts Covered

This question aligns with the NEET Physics syllabus, specifically targeting concepts from General. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

Physicsaveragenonreflectingsurfacenormalincidence

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