A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to ha

Question

A body weighs 72 N on the surface of the earth. What is the gravitational force on it, at a height equal to half the radius of the earth?

Accepted Answer

The weight at height h is given by $W = \frac{mg_0}{(1 + \frac{h}{R})^2}$. Substituting $h = R/2$, we get $W = \frac{72}{(1 + \frac{R/2}{R})^2} = \frac{72}{(3/2)^2} = \frac{72}{9/4} = \frac{72 	imes 4}{9} = 32 	ext{ N}$.

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