A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27$^{\circ}$C. Its density is : (R = 8

Question

A cylinder contains hydrogen gas at pressure of 249 kPa and temperature 27$^{\circ}$C. Its density is : (R = 8.3 J mol$^{-1}$ K$^{-1}$)

Accepted Answer

Using $PM = ho RT$, we get $ho = \frac{PM}{RT}$. Given $P = 249 	imes 10^3$ N/m$^2$, $M = 2 	imes 10^{-3}$ kg, $T = 300$ K. Substituting these, $ho = \frac{(249 	imes 10^3)(2 	imes 10^{-3})}{8.3 	imes 300} = 0.2$ kg/m$^3$.

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