A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre

Question

A long solenoid of 50 cm length having 100 turns carries a current of 2.5 A. The magnetic field at the centre of the solenoid is : ($\mu_0 = 4\pi 	imes 10^{-7} 	ext{ T m A}^{-1}$)

Accepted Answer

Magnetic field at centre of solenoid = $\mu_0 n I$. $n = \frac{N}{L} = \frac{100}{50 	imes 10^{-2}} = 200 	ext{ turns/m}$. $I = 2.5 	ext{ A}$. On putting the values, $B = 4\pi 	imes 10^{-7} 	imes 200 	imes 2.5 = 6.28 	imes 10^{-4} 	ext{ T}$.

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