A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the sc

Question

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is :

Accepted Answer

Least count = $\frac{	ext{Pitch}}{	ext{Number of divisions on circular scale}}$. Therefore, $0.01 	ext{ mm} = \frac{	ext{Pitch}}{50}$, which gives $	ext{Pitch} = 0.5 	ext{ mm}$.

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