An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of

Question

An electron is accelerated from rest through a potential difference of V volt. If the de Broglie wavelength of the electron is $1.227 	imes 10^{-2} 	ext{ nm}$, the potential difference is :

Accepted Answer

$\lambda = \frac{12.27}{\sqrt{V}} 	ext{ \AA}$. $\sqrt{V} = \frac{12.27 	imes 10^{-10}}{1.227 	imes 10^{-11}} = 10^2$. Therefore, $V = 10^4 	ext{ volts}$.

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