The nuclei $_{6}^{13} ext{C}$ and $_{7}^{14} ext{N}$ can be described as:

Question

The nuclei $_{6}^{13}	ext{C}$ and $_{7}^{14}	ext{N}$ can be described as:

Accepted Answer

1. **Formula:** The number of neutrons ($n$) in a nucleus is found by subtracting the atomic number ($Z$) from the mass number ($A$): $n = A - Z$ .
2. **Calculation for Carbon-13 ($_{6}^{13}	ext{C}$):** 
   - Mass Number ($A$) = 13
   - Atomic Number ($Z$) = 6
   - Neutrons = $13 - 6 = 7$
3. **Calculation for Nitrogen-14 ($_{7}^{14}	ext{N}$):**
   - Mass Number ($A$) = 14
   - Atomic Number ($Z$) = 7
   - Neutrons = $14 - 7 = 7$
4. **Conclusion:** Species with different atomic numbers but the same number of neutrons are called **isotones**. Since both nuclei contain exactly 7 neutrons, they are isotones. (Note: Isotopes have the same $Z$, Isobars have the same $A$) .

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