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NEET PHYSICSNUCLEIHard

Question

What is the radius of iodine atom? (atomic no. 53, mass no. 126)

A

2.5 × 10⁻¹¹ m

B

2.5 × 10⁻⁹ m

C

7 × 10⁻⁹ m

D

7 × 10⁻⁶ m

Step-by-Step Solution

  1. Atomic Radius: The atomic radius of an iodine atom is approximately 133 \pm (1.33×10101.33 \times 10^{-10} m) .
  2. Nuclear Radius: The radius of a nucleus is calculated using R=R0A1/3R = R_0 A^{1/3}, where R01.1×1015R_0 \approx 1.1 \times 10^{-15} m and AA is the mass number. For Iodine-126: R1.1×1015×(126)1/31.1×5×10155.5×1015R \approx 1.1 \times 10^{-15} \times (126)^{1/3} \approx 1.1 \times 5 \times 10^{-15} \approx 5.5 \times 10^{-15} m .
  3. Discrepancy: The provided probable answer (2.5×10112.5 \times 10^{-11} m) does not match the standard atomic radius (1.3×1010\sim 1.3 \times 10^{-10} m) or the nuclear radius (5.5×1015\sim 5.5 \times 10^{-15} m). It is significantly smaller than the atomic radius and much larger than the nuclear radius. The question might refer to a specific context not fully captured or contains a data error.

Exam Context & Concepts Covered

This question aligns with the NEET PHYSICS syllabus, specifically targeting concepts from NUCLEI. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

PHYSICSNUCLEIradiusiodineatomic

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