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A ball is projected with velocity $v_0$ at an angle of elevation $30^{\circ}$. Mark the correct statement.
The viscous drag acting on a metal sphere of diameter $1 \text{ mm}$, falling through a fluid of viscosity $0.8 \text{ Pa-s}$ with a velocity of $2 \text{ m s}^{-1}$ is nearly equal to:
A particle is moving in a horizontal circle with constant speed. It has constant:
A boat crosses a river with a velocity of $8 \text{ km/h}$. If the resulting velocity of boat is $10 \text{ km/h}$, then the velocity of river water is:
A particle moves so that its position vector is given by $\mathbf{r} = \cos(\omega t)\hat{x} + \sin(\omega t)\hat{y}$ where $\omega$ is a constant. Based on the information given, which of the following is true?
A particle has an initial velocity $(3\hat{i} + 4\hat{j})$ and an acceleration $(0.4\hat{i} + 0.3\hat{j})$. Its speed after $10 \text{ s}$ is:
The human body does not produce:
The angular speed of a flywheel making 120 revolutions/minute is:
The figure shows a body of mass $m$ moving with a uniform speed $v$ along a circle of radius $r$. The change in velocity in going from $A$ to $B$ is:
The major product formed in the following conversion is: [Reaction Image Missing - Context suggests Alcohol Dehydration]
The stress-strain curves are drawn for two different materials $X$ and $Y$. It is observed that the ultimate strength point and the fracture point are close to each other for material $X$ but are far apart for material $Y$. We can say that the materials $X$ and $Y$ are likely to be (respectively):
A particle moves in a circle of radius 5 cm with constant speed and time period 0.2π s. The acceleration of the particle is:
The velocity of a projectile at the initial point A is $(2\hat{i} + 3\hat{j}) \text{ m/s}$. Its velocity (in m/s) at the point B (landing point on the same horizontal plane) is:
A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 ms⁻², the velocity with which it hits the ground is:
If the equation for the displacement of a particle moving on a circular path is given by $\theta = 2t^3 + 0.5$ where $\theta$ is in radians and $t$ in seconds, then the angular velocity of the particle after 2 sec from its start is:
The position of a particle is given by $\vec{r}(t) = 4t\hat{i} + 2t^2\hat{j} + 5\hat{k}$, where $t$ is in seconds and $r$ in metres. Find the magnitude and direction of the velocity $v(t)$, at $t=1$ s, with respect to the x-axis.
Two particles $A$ and $B$ are moving in a uniform circular motion in concentric circles of radii $r_A$ and $r_B$ with speeds $v_A$ and $v_B$ respectively. Their time periods of rotation are the same. The ratio of the angular speed of $A$ to that of $B$ will be:
A ball is projected from point $A$ with velocity $20 \text{ m s}^{-1}$ at an angle $60^{\circ}$ to the horizontal direction. At the highest point $B$ of the path (as shown in figure), the velocity $v$ (in $\text{m s}^{-1}$) of the ball will be:
A boy standing at the top of a tower of 20 m height drops a stone. Assuming g = 10 m/s², the velocity with which it hits the ground will be:
Parsec is a unit of :