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NEET CHEMISTRYCoordination CompoundsEasy

Question

The complexes [Co(NH3)6][Cr(CN)6][Co(NH_3)_6][Cr(CN)_6] and [Cr(NH3)6][Co(CN)6][Cr(NH_3)_6][Co(CN)_6] show:

A

Ionisation isomerism

B

Co-ordination isomerism

C

Geometrical isomerism

D

Linkage isomerism

Step-by-Step Solution

Coordination isomerism arises in compounds where both the cation and anion are complex entities. It involves the interchange of ligands between the cationic and anionic coordination spheres of different metal ions.

In the given example:

  1. In [Co(NH3)6][Cr(CN)6][Co(NH_3)_6][Cr(CN)_6], the ammonia ligands are bound to Cobalt (CoCo) and cyanide ligands to Chromium (CrCr).
  2. In its isomer [Cr(NH3)6][Co(CN)6][Cr(NH_3)_6][Co(CN)_6], the ammonia ligands are bound to Chromium (CrCr) and cyanide ligands to Cobalt (CoCo).

Since the ligands (NH3NH_3 and CN−CN^-) have been interchanged between the two metal centers, this is a classic example of coordination isomerism .

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundscomplexesconhcrcncrnhcocn

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The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

A.4
B.0
C.2
D.3
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Among the given complexes, the complex having the highest paramagnetic behaviour is: (At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30)

A.$[Zn(NH_3)_6]^{2+}$
B.$[Ti(NH_3)_6]^{3+}$
C.$[Cr(NH_3)_6]^{3+}$
D.$[Co(NH_3)_6]^{3+}$
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Mg is present in:

A.Chlorophyll
B.Haemoglobin
C.Vitamin-B12
D.Vitamin-B
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The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

A.Ionisation isomerism
B.Coordination isomerism
C.Geometrical isomerism
D.Linkage isomerism
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The coordination compound that gives the maximum number of isomers is:

A.$[Co(NH_3)_4Cl_2]$
B.$[Ni(en)(NH_3)_4]^{2+}$
C.$[Ni(C_2O_4)(en)_2]$
D.$[Cr(SCN)_2(NH_3)_4]^+$
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$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

A.$Cu(OH)_2$
B.$Cu(NO_3)_2$
C.$[Cu(H_2O)_4]^{2+}$
D.None of the above
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CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

A.[Co(H₂O)₆]³⁺
B.[Co(NH₃)₆]³⁺
C.[Co(CN)₆]³⁻
D.[Co(C₂O₄)₃]³⁻
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The IUPAC name of the following complex is: $[Ag(H_2O)_2][Ag(CN)_2]$

A.Diaquasilver(I) dicyanidoargentate(I)
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C.Diaquasilver(II) dicyanidoargentate(II)
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