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NEET CHEMISTRYClassification of Elements and Periodicity in PropertiesMedium

Question

The first ionization potential of Be and B will be:

A

8.8 and 8.8

B

6.6 and 6.6

C

6.6 and 8.8

D

8.8 and 6.6

Step-by-Step Solution

Generally, ionization enthalpy increases across a period. However, the first ionization enthalpy of boron (Z=5Z=5) is slightly less than that of beryllium (Z=4Z=4). This is because in beryllium, the electron is removed from the 2s2s orbital (1s22s21s^2 2s^2), while in boron, it is removed from the 2p2p orbital (1s22s22p11s^2 2s^2 2p^1). The 2s2s electron penetrates closer to the nucleus than the 2p2p electron and is more strongly attracted. Additionally, the 2p2p electron in boron is more shielded by the inner core electrons than the 2s2s electrons of beryllium. Therefore, it is easier to remove the 2p2p electron from boron, resulting in a lower ionization energy compared to beryllium , . The only option reflecting the trend IE1(Be)>IE1(B)IE_1(Be) > IE_1(B) is Option D.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Classification of Elements and Periodicity in Properties. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYClassification of Elements and Periodicity in Propertiesionizationpotential

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