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NEET CHEMISTRYCoordination CompoundsMedium

Question

The most stable compound, among the following, is:

A

[Co(NH3)6]2(SO4)3[Co(NH_3)_6]_2(SO_4)_3

B

[Co(NH3)4(H2O)Br](NO3)2[Co(NH_3)_4(H_2O)Br](NO_3)_2

C

[Co(NH3)3(NO3)3][Co(NH_3)_3(NO_3)_3]

D

[CoCl2(en)2]NO3[CoCl_2(en)_2]NO_3

Step-by-Step Solution

When a di- or polydentate ligand uses its two or more donor atoms simultaneously to bind a single metal ion, it forms a chelate complex. Such complexes, called chelate complexes, tend to be more stable than similar complexes containing only unidentate ligands . This extra stability is known as the chelating effect. Among the given options, only [CoCl2(en)2]NO3[CoCl_2(en)_2]NO_3 contains a chelating ligand, ethylenediamine (enen), which is a didentate ligand . The other complexes contain only unidentate ligands (NH3NH_3, H2OH_2O, Br−Br^-, NO3−NO_3^-) . Therefore, [CoCl2(en)2]NO3[CoCl_2(en)_2]NO_3 is the most stable compound.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundsstablecompoundfollowing

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The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

A.4
B.0
C.2
D.3
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Among the given complexes, the complex having the highest paramagnetic behaviour is: (At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30)

A.$[Zn(NH_3)_6]^{2+}$
B.$[Ti(NH_3)_6]^{3+}$
C.$[Cr(NH_3)_6]^{3+}$
D.$[Co(NH_3)_6]^{3+}$
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Mg is present in:

A.Chlorophyll
B.Haemoglobin
C.Vitamin-B12
D.Vitamin-B
EasySolve

The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

A.Ionisation isomerism
B.Coordination isomerism
C.Geometrical isomerism
D.Linkage isomerism
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The coordination compound that gives the maximum number of isomers is:

A.$[Co(NH_3)_4Cl_2]$
B.$[Ni(en)(NH_3)_4]^{2+}$
C.$[Ni(C_2O_4)(en)_2]$
D.$[Cr(SCN)_2(NH_3)_4]^+$
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$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

A.$Cu(OH)_2$
B.$Cu(NO_3)_2$
C.$[Cu(H_2O)_4]^{2+}$
D.None of the above
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CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

A.[Co(H₂O)₆]³⁺
B.[Co(NH₃)₆]³⁺
C.[Co(CN)₆]³⁻
D.[Co(C₂O₄)₃]³⁻
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The IUPAC name of the following complex is: $[Ag(H_2O)_2][Ag(CN)_2]$

A.Diaquasilver(I) dicyanidoargentate(I)
B.Dicyanidosilver(II) diaquaargentate(II)
C.Diaquasilver(II) dicyanidoargentate(II)
D.Dicyanidosilver(I) diaquaargentate(I)
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