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NEET CHEMISTRYCoordination CompoundsEasy

Question

The name of complex ion, [Fe(CN)6]3−[Fe(CN)_6]^{3-} is :

A

hexacyanoiron (III) ion

B

hexacyanitoferrate (III) ion

C

tricyanoferrate (III) ion

D

hexacyanidoferrate (III) ion

Step-by-Step Solution

In the complex ion [Fe(CN)6]3−[Fe(CN)_6]^{3-}, the ligand is cyanide (CN−CN^-), which is named 'cyanido' in IUPAC nomenclature. Since there are six such ligands, the prefix 'hexa' is used. The overall complex is an anion (indicated by the negative charge), so the name of the central metal iron changes to its Latin root ending with '-ate', making it 'ferrate'. Let the oxidation state of Fe be xx. We calculate the oxidation state as: x+6(−1)=−3⇒x=+3x + 6(-1) = -3 \Rightarrow x = +3. Therefore, the complete IUPAC name is hexacyanidoferrate(III) ion.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundscomplex

More Coordination Compounds Questions

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The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

A.4
B.0
C.2
D.3
MediumSolve

Among the given complexes, the complex having the highest paramagnetic behaviour is: (At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30)

A.$[Zn(NH_3)_6]^{2+}$
B.$[Ti(NH_3)_6]^{3+}$
C.$[Cr(NH_3)_6]^{3+}$
D.$[Co(NH_3)_6]^{3+}$
MediumSolve

Mg is present in:

A.Chlorophyll
B.Haemoglobin
C.Vitamin-B12
D.Vitamin-B
EasySolve

The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

A.Ionisation isomerism
B.Coordination isomerism
C.Geometrical isomerism
D.Linkage isomerism
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The coordination compound that gives the maximum number of isomers is:

A.$[Co(NH_3)_4Cl_2]$
B.$[Ni(en)(NH_3)_4]^{2+}$
C.$[Ni(C_2O_4)(en)_2]$
D.$[Cr(SCN)_2(NH_3)_4]^+$
HardSolve

$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

A.$Cu(OH)_2$
B.$Cu(NO_3)_2$
C.$[Cu(H_2O)_4]^{2+}$
D.None of the above
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CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

A.[Co(H₂O)₆]³⁺
B.[Co(NH₃)₆]³⁺
C.[Co(CN)₆]³⁻
D.[Co(C₂O₄)₃]³⁻
MediumSolve

The IUPAC name of the following complex is: $[Ag(H_2O)_2][Ag(CN)_2]$

A.Diaquasilver(I) dicyanidoargentate(I)
B.Dicyanidosilver(II) diaquaargentate(II)
C.Diaquasilver(II) dicyanidoargentate(II)
D.Dicyanidosilver(I) diaquaargentate(I)
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