Match List-I with List-II:

List-I (Complexes) (A) $[Co(NH_3)_5NO_2]Cl_2$ and $[Co(NH_3)_5ONO]Cl_2$ (B) $[Cr(NH_3)_6][Co(CN)_6]$ and $[Cr(CN)_6][Co(NH_3)_6]$ (C) $[Co(NH_3)_5(SO_4)]Br$ and $[Co(NH_3)_5Br]SO_4$ (D) $[Cr(H_2O)_6]Cl_3$ and $[Cr(H_2O)_5Cl]Cl_2 \cdot H_2O$

List-II (Type of isomer) (I) Ionisation isomerism (II) Coordination isomerism (III) Linkage isomerism (IV) Solvate isomerism

Choose the correct answer from the options given below:

(A) Linkage isomerism arises in a coordination compound containing an ambidentate ligand. In $[Co(NH_3)_5NO_2]Cl_2$ and $[Co(NH_3)_5ONO]Cl_2$, the nitrite ligand binds either through nitrogen or oxygen. (A $\rightarrow$ III) (B) Coordination isomerism arises from the interchange of ligands between cationic and anionic entities of different metal ions present in a complex. (B $\rightarrow$ II) (C) Ionisation isomerism arises when the counter ion in a complex salt is itself a potential ligand and can displace a ligand which can then become the counter ion. Here, $SO_4^{2-}$ and $Br^-$ interchange. (C $\rightarrow$ I) (D) Solvate (hydrate) isomerism differs by whether or not a solvent (water) molecule is directly bonded to the metal ion or merely present as free solvent molecules in the crystal lattice. (D $\rightarrow$ IV) Therefore, the correct match is (A)-(III), (B)-(II), (C)-(I), (D)-(IV).