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NEET CHEMISTRYCoordination CompoundsMedium

Question

[Co(NH3)4(NO2)2]Cl[\text{Co}(\text{NH}_3)_4(\text{NO}_2)_2]\text{Cl} can show:

A

Linkage isomerism, ionization isomerism and optical isomerism.

B

Linkage isomerism, ionization isomerism and geometrical isomerism.

C

Ionisation isomerism, geometrical isomerism and optical isomerism.

D

Ionisation isomerism, geometrical isomerism and optical isomerism.

Step-by-Step Solution

The given complex is [Co(NH3)4(NO2)2]Cl[\text{Co}(\text{NH}_3)_4(\text{NO}_2)_2]\text{Cl}.

  1. It contains the ambidentate ligand NO2−\text{NO}_2^-, which can coordinate through either the nitrogen atom or the oxygen atom. Therefore, it shows linkage isomerism.
  2. The counter ion Cl−\text{Cl}^- can exchange with the ligand NO2−\text{NO}_2^- to form [Co(NH3)4(NO2)Cl]NO2[\text{Co}(\text{NH}_3)_4(\text{NO}_2)\text{Cl}]\text{NO}_2. Thus, it exhibits ionisation isomerism.
  3. It is an octahedral complex of the type [Ma4b2][Ma_4b_2], which exists in two geometrical isomeric forms: cis and trans.
  4. It does not exhibit optical isomerism because both its cis and trans forms possess a plane of symmetry and are optically inactive.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

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The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

A.4
B.0
C.2
D.3
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Among the given complexes, the complex having the highest paramagnetic behaviour is: (At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30)

A.$[Zn(NH_3)_6]^{2+}$
B.$[Ti(NH_3)_6]^{3+}$
C.$[Cr(NH_3)_6]^{3+}$
D.$[Co(NH_3)_6]^{3+}$
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Mg is present in:

A.Chlorophyll
B.Haemoglobin
C.Vitamin-B12
D.Vitamin-B
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The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

A.Ionisation isomerism
B.Coordination isomerism
C.Geometrical isomerism
D.Linkage isomerism
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The coordination compound that gives the maximum number of isomers is:

A.$[Co(NH_3)_4Cl_2]$
B.$[Ni(en)(NH_3)_4]^{2+}$
C.$[Ni(C_2O_4)(en)_2]$
D.$[Cr(SCN)_2(NH_3)_4]^+$
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$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

A.$Cu(OH)_2$
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C.$[Cu(H_2O)_4]^{2+}$
D.None of the above
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CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

A.[Co(H₂O)₆]³⁺
B.[Co(NH₃)₆]³⁺
C.[Co(CN)₆]³⁻
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The IUPAC name of the following complex is: $[Ag(H_2O)_2][Ag(CN)_2]$

A.Diaquasilver(I) dicyanidoargentate(I)
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