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NEET CHEMISTRYCoordination CompoundsEasy

Question

The coordination number of Ni in [Ni(C2O4)3]4−[Ni(C_2O_4)_3]^{4-} is:

A

3

B

6

C

4

D

2

Step-by-Step Solution

In the complex ion [Ni(C2O4)3]4−[Ni(C_2O_4)_3]^{4-}, the central nickel ion is coordinated to three oxalate (C2O42−C_2O_4^{2-}) ligands. The oxalate ion is a didentate (bidentate) ligand, meaning it binds to the central metal atom through two donor oxygen atoms. Therefore, the coordination number of Ni, which is the total number of ligand donor atoms bonded directly to the metal, is 3×2=63 \times 2 = 6.

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundscoordinationnumber

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The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

A.4
B.0
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Mg is present in:

A.Chlorophyll
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C.Vitamin-B12
D.Vitamin-B
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The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

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B.Coordination isomerism
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The coordination compound that gives the maximum number of isomers is:

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$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

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CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

A.[Co(H₂O)₆]³⁺
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A.Diaquasilver(I) dicyanidoargentate(I)
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