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NEET CHEMISTRYCoordination CompoundsEasy

Question

The correct order of increasing field strength of ligands is:

A

SCN−<F−<CN−<C2O42−SCN^- < F^- < CN^- < C_2O_4^{2-}

B

F−<SCN−<C2O42−<CN−F^- < SCN^- < C_2O_4^{2-} < CN^-

C

CN−<C2O42−<SCN−<F−CN^- < C_2O_4^{2-} < SCN^- < F^-

D

SCN−<F−<C2O42−<CN−SCN^- < F^- < C_2O_4^{2-} < CN^-

Step-by-Step Solution

The crystal field splitting energy (Δo\Delta_o) depends on the nature of the ligand. Ligands are arranged in a series called the spectrochemical series based on the increasing order of the field strength they produce.

According to the NCERT textbook, the order is: I−<Br−<SCN−<Cl−<S2−<F−<OH−<C2O42−<H2O<NCS−<edta4−<NH3<en<CN−<COI^- < Br^- < SCN^- < Cl^- < S^{2-} < F^- < OH^- < C_2O_4^{2-} < H_2O < NCS^- < edta^{4-} < NH_3 < en < CN^- < CO

Comparing the specific ligands given in the options:

  1. SCN−SCN^- (thiocyanate) is a weak field ligand (appearing early in the series).
  2. F−F^- (fluoride) is a weak field ligand but stronger than SCN−SCN^-.
  3. C2O42−C_2O_4^{2-} (oxalate) is stronger than F−F^- (it produces a larger splitting).
  4. CN−CN^- (cyanide) is a very strong field ligand (appearing near the end of the series).

Therefore, the correct increasing order is SCN−<F−<C2O42−<CN−SCN^- < F^- < C_2O_4^{2-} < CN^- .

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundscorrectincreasingstrengthligands

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