The shape of $Fe(CO)_5$ is:

The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

Among the given complexes, the complex having the highest paramagnetic behaviour is: (At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30)

Mg is present in:

The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

The coordination compound that gives the maximum number of isomers is:

$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

The IUPAC name of the following complex is: $[Ag(H_2O)_2][Ag(CN)_2]$