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NEET CHEMISTRYCoordination CompoundsMedium

Question

The total number of possible isomers for the complex [Co(en)2Cl2]Cl[Co(en)_2Cl_2]Cl are: [enen - ethylenediamine]

A

2

B

1

C

3

D

4

Step-by-Step Solution

The complex [Co(en)2Cl2]Cl[Co(en)_2Cl_2]Cl contains the complex cation [Co(en)2Cl2]+[Co(en)_2Cl_2]^+. This complex ion exhibits both geometrical and optical isomerism.

  1. Geometrical Isomerism: It can exist in cis and trans spatial arrangements.
  2. Optical Isomerism: The trans-isomer possesses a plane of symmetry and is thus optically inactive (achiral). However, the cis-isomer lacks a plane of symmetry and is optically active, existing as a pair of non-superimposable mirror images (dextro and laevo enantiomers). Therefore, the total number of possible stereoisomers is 3 (one trans isomer and two enantiomeric cis isomers).

Exam Context & Concepts Covered

This question aligns with the NEET CHEMISTRY syllabus, specifically targeting concepts from Coordination Compounds. Mastering this topic is crucial for scoring well in the upcoming medical entrance examinations. Solving conceptually related problems will help you understand the nuances of these concepts and improve your problem-solving speed.

CHEMISTRYCoordination Compoundsnumberpossibleisomerscomplexcoenclcl

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The complex, $[\text{Pt}(\text{Py})(\text{NH}_3)\text{BrCl}]$ will have how many geometrical isomers?

A.4
B.0
C.2
D.3
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Among the given complexes, the complex having the highest paramagnetic behaviour is: (At. No. Ti = 22, Cr = 24, Co = 27, Zn = 30)

A.$[Zn(NH_3)_6]^{2+}$
B.$[Ti(NH_3)_6]^{3+}$
C.$[Cr(NH_3)_6]^{3+}$
D.$[Co(NH_3)_6]^{3+}$
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Mg is present in:

A.Chlorophyll
B.Haemoglobin
C.Vitamin-B12
D.Vitamin-B
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The complexes $[\text{Co}(\text{NH}_3)_6][\text{Cr}(\text{CN})_6]$ and $[\text{Cr}(\text{NH}_3)_6][\text{Co}(\text{CN})_6]$ are examples of:

A.Ionisation isomerism
B.Coordination isomerism
C.Geometrical isomerism
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The coordination compound that gives the maximum number of isomers is:

A.$[Co(NH_3)_4Cl_2]$
B.$[Ni(en)(NH_3)_4]^{2+}$
C.$[Ni(C_2O_4)(en)_2]$
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$[Cu(NH_3)_4]^{2+}$ reacts with $HNO_3$ in excess of water and gives:

A.$Cu(OH)_2$
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D.None of the above
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CFSE (in the octahedral field) will be maximum in: (Atomic number Co = 27)

A.[Co(H₂O)₆]³⁺
B.[Co(NH₃)₆]³⁺
C.[Co(CN)₆]³⁻
D.[Co(C₂O₄)₃]³⁻
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The IUPAC name of the following complex is: $[Ag(H_2O)_2][Ag(CN)_2]$

A.Diaquasilver(I) dicyanidoargentate(I)
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